bash does not provide a return statement to return custom values from a function. The return statement is only used to return a numeric status code to the calling function which can be retrieved with $?. Long story made short, use a recent bash version (>= 4.3) and use the declare -n statement to declare a reference to the variable where the result will be stored, and pass the name of this variable as a parameter to the function:
#!/bin/bash
someFunction() {
declare -n __resultVar=$1
local someValue="Hello World"
# The next statement assigns the value of the local variable to the variable
# passed as parameter
__resultVar=${someValue}
}
# call the function and pass the name of the result variable
someFunction theResult
echo ${theResult}